Electrochemical fluorination of organic compounds.
5. Stages of the process of electrochemical fluorination of organic compounds. i 1 =Ó - ( Ó - k 1[ ónHm]0)ÅÈÒ(-k 1t ) . For the second stage it should be written: i 2 =k2[
ón FHm
-1] = - ( Because the concentration of the first intermediate increases by means of its appearance in the first stage and reduces by means of its consumption in the second stage, its full derivative is added from partial derivatives for 1 and 2 stages and is equal to the difference of the partial currents for these stages:
d [CnF H m-1]/d t =( = Ó - (Ó - k 1[ ónHm]0)ÅÈÒ(-k 1t ) -k 2[ ón FHm -1] Solving this equation under the boundary conditions when at t = 0, [ ónFH m-1] = 0 and with the variable exchange [ónFH m-1] = È*ÅÈÒ(-k 2t ) we obtain for [ ónFH m-1] ={ Ó/k 2 -(Ó- k 1[ ónHm]0)ÅÈÒ(-k 1t )/(k 2 - k 1) - k 1(Ó- k 2[ ónHm]0)ÅÈÒ(-k 1t )/k 2(k 1- k2), and for i 2 = Ó - k 2(Ó - k 1[ ónHm]0)ÅÈÒ(-k 1t )/(k 2 - k 1) - k 1(Ó - k 2[ ónHm]0)ÅÈÒ(-k 2t )/(k 1- k2) Similarly one can solve the equation for the subsequent stages of fluorination, for the third stage in particular:
Accordingly the partial current density for the last stage of the process or the rate of the end product formation will be expressed by the equation:
, where x is not equal to y. The rates of the last stage will be influenced only by decelerated stages of the process for which ky>>kx. Under these conditions constants ky existing in the fractional products will be contracted and one can neglect the exponential terms with constants differing by an order of magnitude from the constants of the decelerated stages. If the process includes only one decelerated stage ( obviously, electrochemical one) , the equation becomes considerably more simple and reduces to the equation: i m =Ó - (Ó - k Á[ ónHm]0)ÅÈÒ(-k Át ) similar to the given one for the partial current density for the first stage. In this case the rate of the last stage and consequently the current yield of the end product will increase monotonically with time asymptotically approaching Ó = d [CnHm]/d as it is shown in Fig.8. In the absence of the starting substrate feeding during the electrolysis, when the concentration of the starting substrate decreases with its consumption in fluorination, i.e. at c=0 the equation is expressed as follows:
At t=0 im=0 in accordance with the boundary
conditions , at t -- > The current yield of a process of electrochemical fluorination involved z electrones is A=zFd[CnHm]/dQ, where Q is the amount of electricity passed. The electrolysis current J is equal to dQ/dt and hence, at a constant electrolysis current , the current yield is equal to:
Evidently, the derivative of the end product concentration with respect to time is the rate of this product formation, i.e. the rate of the last stage of the electrolysis process. The current yield may be expressed as a ratio of the amount of electricity consumed for the given end product to the total amount of electricity passed , %. It is not difficult to calculate this value in case of the formation of an individual product when the amount of expendable Faradeys is known. But in electrochemical fluorination there is produced a lot of products due to a variety of accompanying processes, so it is not always possible to calculate the current yield and in this case it is evaluated in g/A-hour. According to the analysis performed, in the absence of the starting substrate feed, methyl-3-methoxypropionate in particular, in the electrolysis with electrolyte exhausting the experimental dependence of the current yield in g/A-hour has a form of a rather symmetrical curve with a maximum given in Fig.9. In the lasting continuous electrolysis with the starting substrate feed to the elctrolyzer to keep a stationary electrolyte concentration, the current yield will conform to the equation:
At Ó = k 1[ ónHm]0 when the starting substrate feed to the elctrolyzer is equal to its consumption in the first stage and its concentration is not changing during the course of the process, the equation for the current yield can be written:
and at t =0 A=0 according to the boundary conditions , at
The value k1 can not be determined strictly due to a variety of reactions of destruction, cyclization, isomerixation and so on, which probably precede the fluorination . That is why one has to calculate the value of starting compound feed "c" in accordance with the electricity consumption for fluorination in the electrolysis with one-time loading. Usually, such a calculated value is slightly lower than k1 [CnHm]0 because in this electrolysis an instant comes when there is no starting substrate in the elctrolyte and the current is still consuming for fluorination of intermediates and this value is to be refined experimentally. In conformity with mathematical analysis, at c < k1 [CnHm]0 the current yield at a real conditions passes through a maximum reducing with time due to the electrolyte exhaustion as it is shown in Fig.11. The attempts to correct the electrolyte content by one-time additions of the starting product surprisingly resulted in a considerable reduction in the current yield as it follows from Fig.11. The analysis of the given equation for the current yield
indicates that if a slowed down stage of the
process is the first one, at a change of the concentration [
ónHm]0+ Such an extreme drop in the current yield of the end products at one-time correction results in a reduction in the average current yield and hence, in the electrolyzer capacity. Also this brings to a noticeable scatter of the values to be determined, which is associated with batch nature of the starting product feed into the electrolyzer in the lasting continuous process. This phenomena is not observed at continuous feed by a dozing pump. Overfeeding the starting product resulted also in a reduction in the current yield due to an accumulation of resin type high molecular products in the electrolyte, but this is a subject of a special consideration. Thus, the performed formal kinetic analysis of multistage nature of ECF has been convincingly confirmed in the electrochemical fluorination of methyl-3-methoxypropionate and some other oxygen-containing compounds and may be probably used in continuous electrolysis of different compounds. Conclusions
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